KCC's Quizzes AQQ287 about throwing 3 dice

1. Mean value of a dice is (1+2+3+4+5+6)/6 = 3.5

To know the value S where probability P(S) is the maximum, it must be in the mean value.

Here for 3 dice, mean value is 3.5*3 = 10.5.

So the value S where probability P(S) is the maximum are 10 and 11 (same probability).

2. For n number of dice --> S for which P(S) is maximum = 3.5*n.

It took me a while to figure out the solution, because I initially (and mistakenly) thought the average value of a die was 6 divided by 2. Maybe my background in electronics is to blame... As we always start counting from 0! 

Thanks for this nice puzzle KC !

1. Mean value of a dice is (1+2+3+4+5+6)/6 = 3.5

To know the value S where probability P(S) is the maximum, it must be in the mean value.

Here for 3 dice, mean value is 3.5*3 = 10.5.

So the value S where probability P(S) is the maximum are 10 and 11 (same probability).

2. For n number of dice --> S for which P(S) is maximum = 3.5*n.

It took me a while to figure out the solution, because I initially (and mistakenly) thought the average value of a die was 6 divided by 2. Maybe my background in electronics is to blame... As we always start counting from 0! 

Thanks for this nice puzzle KC !

Congratulations FlorentDENIS ! The most frequent sum is indeed 3.5 n with n the number of dice. 3.5 n if n is even and 3.5 n +/-0.5 if n is odd. You are in fact nearly there! The only difficult point is what is the probability? I confess I on't have the answer; and count on a miraculous participant...