KCC's Quizzes AQQ287 about throwing 3 dice

With 3 dice, the range of sums will be from 3 to 18 and the most common sums will be 10 and 11 with equal probability of 27 times out of 216 - P(10) = P(11) = 27/216 = 0.125.

With n dice, the probability of rolling a particular number on any die is the same and is 1/s where s is the number of sides so 1/6 in this case.  For two dice or more, the number of permutations is given by s^n = 6^2 = 36 for two dice rolls and 6^3 = 216 for three dice rolls.  The sum of the rolls follow a gaussian distribution as there are 6 ways of getting 7 with a 2 rolls but only one way of getting 2 or 12.  The range of values will be integers from n to 6n for a 6-sided dice and the most probable sum will be median value (or two values if the number of dice is odd).

With 3 dice, the range of sums will be from 3 to 18 and the most common sums will be 10 and 11 with equal probability of 27 times out of 216 - P(10) = P(11) = 27/216 = 0.125.

With n dice, the probability of rolling a particular number on any die is the same and is 1/s where s is the number of sides so 1/6 in this case.  For two dice or more, the number of permutations is given by s^n = 6^2 = 36 for two dice rolls and 6^3 = 216 for three dice rolls.  The sum of the rolls follow a gaussian distribution as there are 6 ways of getting 7 with a 2 rolls but only one way of getting 2 or 12.  The range of values will be integers from n to 6n for a 6-sided dice and the most probable sum will be median value (or two values if the number of dice is odd).

Great answers and reasoning MTF_Walker ! Thus for n dice, the median value for the sum is n+((6n-2)/2 or 7n/2. If n s even it is just 7n/2 and 7/n/2 +/-0.5 if n is odd. But what is the probability to get that sum? I have to confess I don( have the answer...