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KCC's Quizzes AQQ283 about Weighting Alphabetic Letters

1. Quote of the week: "Customers are like teeth. Ignore them and they'll go away" - Jerry Flanagan

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2. New challenge: AQQ283: Weighting alphabetic letters

A certain weighting coding is associated to each alphabetic letters in the following sequence:

A = 1

B = A+1

C= A+B+1

D= A+B+C+1

Etc…

What will be the value for Z?

Good luck and try to be among the first ones!

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  • The proof is easy if we write the result in binary:  0000...0001 =A
                                                                                +0000...0010 =B = A + 1
                                                                                +0000..0100 = C = B+A+1
                                                                                        etc. which is a sequence of 2^(n-1)

            

Reply
  • The proof is easy if we write the result in binary:  0000...0001 =A
                                                                                +0000...0010 =B = A + 1
                                                                                +0000..0100 = C = B+A+1
                                                                                        etc. which is a sequence of 2^(n-1)

            

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