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KCC's Quizzes AQQ283 about Weighting Alphabetic Letters

		
	
				

			

									
					    KCC
					
							

            
            			
				
									
											
			
			
				
  •  Analog Employees  

			
			
			    	
			                    
                
				                on Mar 27, 2025 
				
			
			
		

		
		                     
				
        		

		    
		    		    
		    			

			    
1. Quote of the week: "Customers are like teeth. Ignore them and they'll go away" - Jerry Flanagan


 


Source: https://source.roboflow.com/A93JwBkvTQWfUenUZzdVjMVkIh33/3jgAFSPcyf0GIvIvn0cq/original.jpg


2. New challenge: AQQ283: Weighting alphabetic letters


 


A certain weighting coding is associated to each alphabetic letters in the following sequence:


A = 1


B = A+1


C= A+B+1


D= A+B+C+1


Etc…


What will be the value for Z?


Good luck and try to be among the first ones!







			

			
									
		                             
                        

    

                                            
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    •  Analog Employees  
    
            
						
                            
            
            				
            
                on Mar 27, 2025 7:06 AM
            
            
						
			            		
    
		
								
	
    

		
		
    
		
    
                                
                                                            
    
					
    This sequence is cumulative in nature, where each letter's value is determined by adding 1 plus the sum of all previous letter values. Notice the pattern: each value doubles the previous one
    

    A = 1
    B = A + 1 = 1 + 1 = 2
    C = A + B + 1 = 1 + 2 + 1 = 4
    D = A + B + C + 1 = 1 + 2 + 4 + 1 = 8
    E = 16
    F = 32
    Z = 2^(26 - 1) = 2^25
    The value for Z is therefore 33,554,432
    
			
    

		
			
	      

		
		
	
    
	
    
		
    
			
		
    
	
    
	
    
		
						
				
				
						
				
				
		
		
    
			
		
    
	
    

    

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Reply

    


  • 
	
    






    
	
    
		
    
							
					
    
		
    
		    
		    		    
			
				
									
							        
			
			
			
    •  Analog Employees  
    
            
						
                            
            
            				
            
                on Mar 27, 2025 7:06 AM
            
            
						
			            		
    
		
								
	
    

		
		
    
		
    
                                
                                                            
    
					
    This sequence is cumulative in nature, where each letter's value is determined by adding 1 plus the sum of all previous letter values. Notice the pattern: each value doubles the previous one
    

    A = 1
    B = A + 1 = 1 + 1 = 2
    C = A + B + 1 = 1 + 2 + 1 = 4
    D = A + B + C + 1 = 1 + 2 + 4 + 1 = 8
    E = 16
    F = 32
    Z = 2^(26 - 1) = 2^25
    The value for Z is therefore 33,554,432
    
			
    

		
			
	      

		
		
	
    
	
    
		
    
			
		
    
	
    
	
    
		
						
				
				
						
				
				
		
		
    
			
		
    
	
    

    

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