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KCC's quiz AQQ274 about 2 sportsmen running and walking

Two  sportsmen A and B have exactly the same running speed and the same walking speed.

One day they started the same trip to the same place.

Sportsman-A walked for half of the distance and ran for the rest, while

Sportsman-B walked for half the time and ran for the other half of time.

Question: Which sportsman reached the end of the trip first? How do you justify it?

Good luck and try to be among the firsts!

P.S. Pass those quizzes among your colleagues and friends; we all need such small brainstorming time to time!

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Parents
  • This is a nice easy problem as the only thing you need to know is

    Distance = Speed x Time   D=S.T

    For starters, let’s assume walking is 5 km/h and running is 10 km/h, and their distance is 10 km.

     

    Take the case of Sportsman A walking and running each for half of the time:

    T/2 x 10   +    T/2 x 5  = 10

    So 7.5T = 10, the time to complete the course is 10/7.5 = 1.33 hours.

     

    In the other case - Sportsman B - we need 2 times, T1 and T2:

    T1 x 10 = 5   so T1 must be 0.5 hours

    T2 x 5 = 5      so T2 must be 1 hour

    Total time is thus 1.5 hours.

     

    So it is better to run and walk each for half of the time - ie B will be faster.

    A bit of work with Excel confirmed that as long as the running speed is more than the walking speed, this strategy will work, as long as Sportsman B knows his walking and running speeds, and can do the math and can calculate the times he has to run and walk!

Reply
  • This is a nice easy problem as the only thing you need to know is

    Distance = Speed x Time   D=S.T

    For starters, let’s assume walking is 5 km/h and running is 10 km/h, and their distance is 10 km.

     

    Take the case of Sportsman A walking and running each for half of the time:

    T/2 x 10   +    T/2 x 5  = 10

    So 7.5T = 10, the time to complete the course is 10/7.5 = 1.33 hours.

     

    In the other case - Sportsman B - we need 2 times, T1 and T2:

    T1 x 10 = 5   so T1 must be 0.5 hours

    T2 x 5 = 5      so T2 must be 1 hour

    Total time is thus 1.5 hours.

     

    So it is better to run and walk each for half of the time - ie B will be faster.

    A bit of work with Excel confirmed that as long as the running speed is more than the walking speed, this strategy will work, as long as Sportsman B knows his walking and running speeds, and can do the math and can calculate the times he has to run and walk!

Children