KCC's Quizzes AQQ272 about a division giving its double

You can write this as x/x = 2x and multiplying both sides by x arrive at x = 2x^2

Rearranging, we get 2x^2 – x = 0 then factoring we get x(2x-1) = 0

For the equation to be zero, either factor must be zero

So, either x = 0 or 2x-1=0 => x=0.5, so the number is either 0 or 0.5

Anything divided by zero is undefined, so strictly-speaking the only solution is 0.5.

You can write this as x/x = 2x and multiplying both sides by x arrive at x = 2x^2

Rearranging, we get 2x^2 – x = 0 then factoring we get x(2x-1) = 0

For the equation to be zero, either factor must be zero

So, either x = 0 or 2x-1=0 => x=0.5, so the number is either 0 or 0.5

Anything divided by zero is undefined, so strictly-speaking the only solution is 0.5.

Brillant reasoning MTF_Walker , fully correct!