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KCC' Quizzes AQQ270 about a difference amplifier challenge

1. Quote of the week: 

2. New challenge AQQ270 about a Difference Amplifier challenge (this is a proposal from our colleague

Martin Walker, Product Marketing Leader at ADI UK – warm thanks to him!):

Below is the classic difference amplifier circuit.

Questions:

 1. What is the Common Mode Rejection Ratio (CMRR) if we have perfectly matched resistors?  [Assume the amplifier’s CMRR is 120dB]

 2. What is the CMRR if the resistors have a tolerance of 0.1%?

 3. What is the CMRR if the resistors have a tolerance of 1%?

 4. What input resistance does V2 ‘see’?

 5. What input resistance does V1 ‘see’?

 6. If the difference amplifier was AC-coupled, what impact would this inequality in input impedance have?

Good luck!

Edit Notes

removed inappropriate Quote
[edited by: GenevaCooper at 1:18 PM (GMT -4) on 20 Sep 2024]
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  • 1. CMRR=120

    2. CMRR(dB) = 20*log(1/t) => 20*log(0.1/100) =>20*log(1000) which is 60dB

    3. 20* log(1/t) => which is 20*2 => 40dB

    4. Input resistance by v2 will be r3+r4=2kohm

    5. Input resistance by v1 will be When V1 and v2  are equal and opposite in phase, this feedback can reduce the effective impedance at V1, making it less than 1kohm

    6. Mismatch in input impedance cause the input frequncy to differ  which may affect the signal fidelity especially in ac couploed. 

  • It's interesting to simulate this problem, both to calculate the CMRR = 20*log | Adiff / Acm | and the apparent value of R1 with respect to V1.

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