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KCC's Quizzes AQQ253 about a funny equation



		

			

									
					    KCC
					
							

			
				
									
											
			
			
				
  •  Analog Employees  

			
			
			    	
			                    
                
				                on Feb 13, 2024 
				
			
			
		


				
		

		    		    
		    
		    	
			
And here is a new challenge! It's easier than the previous one but still...


 


Please spread those weekly quizzes among your colleagues!


Also, please be informed awards and goodies are being sent to the frequent winners. Please apologize for the long delay since we do that only 2 times per year!


 Certificates of the wins are also sent in paper form; the ones desiring a digital copy, please let us know!


Some statistics about the frequent winners by country origins: (we have also statistics by individuals, but they can be provided on demand and only with own data).


 


Regards


Kuo-Chang

									
			        
		


				
						
        

    
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                on Feb 15, 2024 8:33 AM
            
            
					
      
	
      

		
		
      
					
      8^x + 2^x = 130
      

      Assume 2^x = t then the equation will become t^3+t-130 = 0
      

      So possible value of t will be 5 so then equation will be (t - 5) (t^2+5t+26) = 0.
      

      And t^2+5t+26 will give us imaginary roots because discrimant is 5*5-4*1*26 which is negative so possible value of t is 5 
      

      Hence value of x is log5/log2 which is 2.3219
      

      Ans 2.3219
      
			
      

		
			
	      

		
		
	
      
	
      
		
      
			
		
      
	
      
	
      
		
						
				
				
						
				
				
		
		
      
			
		
      
	
      

      

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                on Feb 15, 2024 8:33 AM
            
            
					
        
	
        

		
		
        
					
        8^x + 2^x = 130
        

        Assume 2^x = t then the equation will become t^3+t-130 = 0
        

        So possible value of t will be 5 so then equation will be (t - 5) (t^2+5t+26) = 0.
        

        And t^2+5t+26 will give us imaginary roots because discrimant is 5*5-4*1*26 which is negative so possible value of t is 5 
        

        Hence value of x is log5/log2 which is 2.3219
        

        Ans 2.3219
        
			
        

		
			
	      

		
		
	
        
	
        
		
        
			
		
        
	
        
	
        
		
						
				
				
						
				
				
		
		
        
			
		
        
	
        

        

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