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# KCC's quizzes AQQ235 about a bipolar common emitter amplifier - a kind proposal from our colleague Martin Walker

Apologize for our non-technical audience since this quiz is more for our FAEs...

A kind proposal from our colleague Martin Walker, ADI Product Marketing Engineer, UK:

Most of our electronic engineers have seen this sort of circuit in their first year study time using a bipolar transistor in its 3 famous basic configurations: common emitter, common collector and common base.

Here above is a common emitter configuration.

Conditions:

• Vcc = 6V
• Vout = 3V
• Tc = 25°C

Q1 is a BJT NPN with current gain β of several hundreds.

RB1 and RB2 are large compared to RC and RS

Questions :

1. Is there enough information to work out the gain of this circuit?
2. If so, what is the voltage gain of the circuit?
3. Is it a good amplifier?
4. If not, what would you do to mitigate for its limitations?

Again, many thanks Martin!

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[edited by: emassa at 2:19 PM (GMT -4) on 22 May 2023]
Parents
• First let's assume by "gain" you mean small signal voltage gain. In that case for the common emitter configuration without an emitter degeneration resistor the gain Av is gm * Rc (a dimensionless ratio) . For a BJT device we know that gm = Ic/Vt (where Vt is the thermal voltage which is about 26 mV at room temperature). We are also given that half of Vcc or 3 V is dropped across Rc so Ic = 3/Rc. Using these equations and solving for Av we get 3V/26mV or about 115. It turns out that the absolute value of Rc drops out in the calculation and all we need to know is that Rb1 and Rb2 are such that the voltage at the collector is as stated in the problem statement.

-DM