In an analog clock, the angle formed by the hour and the minute hands varies constantly.
Questions:
1. θ = 40°
Solution:
θ from 12 for each number = 360° / 12 = 30°
Hour θ movement for each minute = 30° / 60 = 0.5°
For 20 minutes,
number = 4
θ = 4 (30°) = 120°…
1. Which angle θ is obtained when it is 5:20 ?
Long hand: 20 past is 120 degrees from 12:00
Short hand: is 150 degrees + 1/3 of the way between 5 and 6 (30/3 degrees) = 160 degrees
Angle between them…
Each number on clock makes 30°.
The hour hand also moves, so for each minute, it moves 30/60 = 0.5 deg. for 20 minutes it moves 10 deg.
At 5.20 , θ is 40°.
At around 4:5:30, θ is 90°.…
