Special Edition - KCC's Quiz - World Engineering Day Quiz Equivalent Resistance

R_A-B = 2R

At the last chain link the two 2R resistor networks are parallel. This results in R. Another R in series results in 2R again. This is parallel to 2R of the chain link in front of it. This results in R again and so one.

At the first chain link (left side) we have the same situation. Therefore R_A-B = R + R = 2R .

R_A-B = 2R

At the last chain link the two 2R resistor networks are parallel. This results in R. Another R in series results in 2R again. This is parallel to 2R of the chain link in front of it. This results in R again and so one.

At the first chain link (left side) we have the same situation. Therefore R_A-B = R + R = 2R .

Bingo ETecProfi , you get it, congratulations!