need urgent support for questions below.
I'm evaluating EVAL-ADE9000 now.
Regarding the EVAL-ADE9000EBZ schematic, the AC neutral is connected to AGND, which this AGND is directly connected to ADE9000 GND pin.
1st question would like to double confirm with you when we measure the AC voltage source, the AC Line is connect to VAP_IN and AC Neutral is connect to AGND??
As we know, the digital signal for ADE9000 is using the AGND as return path, it is the AC neutral will affect the digital function?
2nd question, our design is the using ARMs through by SPI communication to ADE9000 without using the digital isolated chip(ADUM3150ARSZ), it is got any issue?
3rd question, AC neutral, AGND and DGND connect together, it is our ARMs chip, ADE9000 or DC power regulator circuit can be damaged? or any abnormal situation will happen?
Closed topic as found the answer.
Good to hear that you have found the answer. Will you able to share your answer here in the forum so other people with the same question can also see?
Thank you very much.
Ans: Yes, this is the common method find from all the Power Measurement circuits, due to the IC does not know the reference point of the AC signal, the AC signal always changes, the IC cannot measure the AC voltage correctly, it can measure but not fine. So that’s why the Neutral connected to the AGND.
As we know, the digital signal for ADE9000 is using the AGND as return path, it is the AC neutral will affect the digital function??
Ans: it is ok, this is the common method find from others brand IC manufacturers.
Ans: Not sure ok or not, but if the DC supply of the circuits is isolated, and the ADE9000 is floating, that means the whole circuit is only direct connected to the AC side only, seems that is ok if the ADE9000 not connected to other circuits or the connected circuit are also floating at the same AGND.
3rd question, AC neutral, AGND and DGND connect together, it is our ARMs chip, ADE9000 or DC power regulator circuit can be damaged? or any abnormal situation will happen? Ans: you have to make sure the DC power is isolated, please refer to the last question (2nd question.).