Hi,
I found a paradox in the noise simulation of the circuit below. When I want to measure the output noise current of a voltage to current amplifier I would add a 0V voltage source in series with the load and convert that noise current to a voltage using an H-source, since I don't know how to perform an output noise current simulation directly. Then I could as well leave out the load resistor and add series resistance to my voltage source. When I did that I noticed an increase in the amount of noise, so I reduced that problem to this demonstration circuit.


The noise contribution of R1 is 0, which is makes sense to me since the circuit is open. But the noise contribution of V1, with the same series resistance, is about 4pA/√Hz which is what it would be if V1 is shorted. The same series resistance gives two different results. Could this be fixed?
Best regards,
Danny
-- EDIT --
I have done some more thinking about it and I have reverse engineered a model for the Vsource that would show this behaviour.

Rser itself is noiseless and the noise of Rser is added by G1. This way when the voltage source is unloaded, all of the noise current passes through V1 and shows up at V(out) as a transformed voltage. In reality this can't happen if the circuit is open. There would only be a noise voltage present at the output terminals of the voltage source, without any current. To solve this G1 should be placed in parallel with Rser without including V1 in the loop.
-- END EDIT --
Edit Notes
added a possible model that explains it[edited by: danny1 at 1:25 PM (GMT -5) on 5 Jan 2024]
