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AD5293: shift register DIN with MSB first or least?

Which bit must be sent first from the microcontroller to DIN - bit 15 or bit 0?
The Datasheet contains two conflicting descriptions: In the timing diagram on
page 8, D0 = LSB first sent from the microcontroller. From page 18 'Shift
Register', I understand that bit 15 = MSB is sent first by the microcontroller.
Which description is correct?


The MSB should be shifted first. Figure 4 is probably a bit confusing but when
the data is sampled (falling edge of \SYNC) the data is X.