I plan to use the ±3 V range. Will sending the code 0xFFFF output 3.15 V and 0x000 output -3.15 V?
What will the new equation for the transfer function be with overrange enabled?
Apologies for the late reply. Following the datasheet's transfer function equation, for ±3.15V range, M=2.52 and C=1.26.
The increase in M and C value is also 5%.
To cross verify the constants, you can try to calculate using 2 equations. First, when Vout = +3.15V (D=65535) and another equation when Vout = -3.15V (D=0).
Regards,
Flynn
Apologies for the late reply. Following the datasheet's transfer function equation, for ±3.15V range, M=2.52 and C=1.26.
The increase in M and C value is also 5%.
To cross verify the constants, you can try to calculate using 2 equations. First, when Vout = +3.15V (D=65535) and another equation when Vout = -3.15V (D=0).
Regards,
Flynn
