AD5593R

Dear Sir,

   Would you please help to provide the AD5593R's die temperature individual in ambient-40 and 85°C?

Thank you very much!

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  • Hi ,

    To calculate I need to know more information.

    Please see example below, you can base your own calculations on it.

    AD5593R Configuration:

    - 8 DACs,

    - Internal Reference (2.5V)

    - Gain = 2

    - VDD = 5V, VLogic = 1.8

    - 1k load on each channel

    - Each DAC output = 1V

    IDD = 1.6mA (Datasheet spec table)

    ILogic = 3.5uA (Datasheet spec table)

    Power Consumption (Unloaded) = (1.6mA * 5V) + (3.5uA * 1.8V) = 8mW

    Driving 1V with a 1k load would give a current of 1mA out on each channel.

    The internal amplifiers in the DAC is supplied with 5V. The output of these amplifiers will be 1V. Therefore, 4V must be dropped in the device at 1mA. Power dissipated per channel = 1mA * 4V = 4mW.

    On 8 channels, this is 32mW.

    Total Power Dissipated = 40mW.

    16-lead TSSOP, θJA = 112°C/W.

    Increase in temperature = 4.48°C

    Tj at ambient -40°C = 35.52°C

    Tj at ambient 85°C = 89.48°C

    Regards,

    Mike.

Reply
  • Hi ,

    To calculate I need to know more information.

    Please see example below, you can base your own calculations on it.

    AD5593R Configuration:

    - 8 DACs,

    - Internal Reference (2.5V)

    - Gain = 2

    - VDD = 5V, VLogic = 1.8

    - 1k load on each channel

    - Each DAC output = 1V

    IDD = 1.6mA (Datasheet spec table)

    ILogic = 3.5uA (Datasheet spec table)

    Power Consumption (Unloaded) = (1.6mA * 5V) + (3.5uA * 1.8V) = 8mW

    Driving 1V with a 1k load would give a current of 1mA out on each channel.

    The internal amplifiers in the DAC is supplied with 5V. The output of these amplifiers will be 1V. Therefore, 4V must be dropped in the device at 1mA. Power dissipated per channel = 1mA * 4V = 4mW.

    On 8 channels, this is 32mW.

    Total Power Dissipated = 40mW.

    16-lead TSSOP, θJA = 112°C/W.

    Increase in temperature = 4.48°C

    Tj at ambient -40°C = 35.52°C

    Tj at ambient 85°C = 89.48°C

    Regards,

    Mike.

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