Help in Adjusting the CAPDAC setting

Hi, Kapple .

Can you send a snapshot of your setting? What is your desired setting? Meanwhile, you can try checking these links:

• (5) I am trying to read capacitance value for two different capacitors using the two channels of the AD7746 evalutation board. How can I measure two values by using evaluation software? - Q&A - Precision ADCs - EngineerZone (analog.com)
• (5) Demo code for using EVAL-AD7746LDZ evaluation board - Q&A - Precision ADCs - EngineerZone (analog.com)
• (5) After the AD7746 capacitance range is increased to 0-8pF, how to perform CAPDAC calibration？ - Q&A - Precision ADCs - EngineerZone (analog.com)

Warm regards,
Jo

Thank you Nathan for the reply!

I am not using an evaluation board. I am interfacing a CDC chip with the Arduino. 

Here are some snapshots of my code where I try to change the CAPDAC value. 

Hi, Kapple .

I have already reached out to the product owner. I will get back to you at once when I received feedback.

Thank you and regards,
Jo

Hi Kapple 

we can help and support you if you have any question related to ADC functionality, but we do not provide debugging support because we already provide drivers that have been tested and we know the are functional.

The drives can be found in the following link:

no-OS/drivers/cdc/ad7746 at main · analogdevicesinc/no-OS (github.com)

Saying that I think your Capdac calculation is not correct. The Capdac value is 16 bits so shifting 16 bits to the left the value of byte2 doesn't make sense. Actually I don't understand why you have 3 bytes in the calcualtion.

Regards

Joan

Hi Kapple 

we can help and support you if you have any question related to ADC functionality, but we do not provide debugging support because we already provide drivers that have been tested and we know the are functional.

The drives can be found in the following link:

no-OS/drivers/cdc/ad7746 at main · analogdevicesinc/no-OS (github.com)

Saying that I think your Capdac calculation is not correct. The Capdac value is 16 bits so shifting 16 bits to the left the value of byte2 doesn't make sense. Actually I don't understand why you have 3 bytes in the calcualtion.

Regards

Joan