AD7980 in 4-WIRE CS MODE WITHOUT BUSY INDICATOR, How many AD7980 can be conected in this way? In datasheet, the example of this application is only two parts, if possible, connected three or more?
Hi Sara123 ,
May I know what are the errors you are getting? And may I also know if you are getting any error if you are using only two AD7980? Or are there any confusions when using only two AD7980?
Moreover, for your reference, here are some of my insights to guide you in your concern:
1) Make sure that the digital host you are using also has three Chip Select (CS) since you have stated that you are using three AD7980. The CS of the 1st AD7980 should be held low for you to select the device.
2) Kindly refer to page 21 of the datasheet. It states that after every falling edge of the 16th clock pulse of the SCK, SDO will be held to high impedance while the SDI of the first AD7980 should be held high. And the next AD7980 can be read by being held low. So, the third AD7980 should be held low after the 32nd clock pulse.
Let me know if this would help you so that I could further assist you.
Regards,
Jo
Thanks for your reply.
What Sara123 said was the problem I encountered in my work. My English is not good, her help me ask.
In actual measurement, When CNV rises, all three CS are at high levels.The sck signal is present and not shown in the figure. At position 1840 of the timing chart, after the 16th falling edge of the clock, SDO1 has completed 16 bit data transmission，both SDO2 and SDO3 have signal outputs although all CS are high. I think it ould be because SDO data is valid on both the rising and falling edges of the clock, and SDO must be output before the rising and falling edges of the clock. In this case, connecting SDO together will result in error.
this one
other
All SDOs are connected to Pull-up resistor
All SDO connection pull-down resistors
