i have a circuit that requires the use of AD7862. however in my country (Malaysia) it is not available, and purchasing for outside of the country is time consuming and costly. i asked AD for a pin-compatible IC for replacement and they suggested AD7863.
AD7863 is 14-bit ADC while AD7862 is 12-bit. so the only different in pins is the extra 2 pins at Pin1 and Pin28 (NC at AD7862).
my question is, if i use AD7863 instead of AD7862, and i neglected the use of Pin1 and Pin28, will the circuit run as usual (it is a working circuit by previous students). from my understanding, if i neglected the two pins, then the IC and the circuit will work just as usual with the IC AD7863 is downgraded into 12-bit.
please correct me if i'm wrong, thank you!
Noted with thanks Brendan.
ohh, so it is like that. is it because the AD7863's MSB bit is already set at DB13?
again thank you so much for clarification.