I would like to clarify on the input voltage of the application is maximum at 100V? Please take note on the abs max rating for the AD7264 from -0.3 to AVcc+0.3V (AVcc = 7V).
The AD7264 is a true differential analog input ADC, this means that the input signal is 180 degrees out of phase. for example, At Vref = 2.5V the typical voltage range for the AD7264 is 2.5V. The common mode voltage would be at 1.25V or 3.75V ( Vcm = Vrange+/-(Vref/(2*gain)).
As specified on the datasheet, the AD7264 has common mode voltage range and going beyond this range cannot guarantee product performance. Having a no Vcm or Vcm =0, for the example above at 2.5V range, this would mean that the input signal is from -1.25V to 1.25V. Having this signal range violates the Abs max rating of the part that may cause damage. There are circuit that converts a unipolar single ended signal into a differential signal. Like as an example, on the Figure 26 of the AD7265 datasheet ( http://www.analog.com/media/en/technical-documentation/data-sheets/AD7265.pdf) it uses the AD8022 to configure to differential signal.
Many thanks for the clarification.
The input signal range we have is +/- 100 V differential.
Please confirm / deny my design:
In your application I would suggest to create a current sense circuit. The +/-100V will be in series with a high power small value resistor. The resistor will sense the current passing. The voltage across the resistor will then be measured. There are current sense amplifier available with ADI and you can refer to the web and do parametric search. Please refer to the link http://www.analog.com/en/parametricsearch/11080#/p4133=Instrumentation .
There is also a reference circuit CN0280 which is complete current sense solution. Please refer to this link http://www.analog.com/en/design-center/reference-designs/hardware-reference-design/circuits-from-the-lab/CN0280.html#rd-overview.