Questions about AD7172/5/7-2

Hello Jellenie,

At first a general note, I ask question that about what I could not understand from the data sheet. It is not helpful when you simply copy-paste from it, like you did with questions 7 and 8. Perhaps you just don't know the answer? Or you could ask a clarifiying question if I you don't understannd, what I am asking about.

7. So how do I calculate offset (register) from offset voltage and gain from the gain coefficient?

I would like clear separate formulas Offset=? and Gain=?

8.I need more information about system calibration. Do the voltages have to be applied to both pins? Do they need to be physically applied or the inputs could be simplöy switch to ground for offset calibration and to reference voltage for gain calibration? 

10. I see I used "effective" somewhat misleadingly. What I really asked about is the unipolar mode mentioned on page 24. It says the format is straight binary, but I suspect that it is achieved by making it 2's complement and ignoring the - the negative range and thus the MSB, thus reducing the real resolution by 1 bit. Am I correct?

Thank you for your help

Hello Jellenie,

At first a general note, I ask question that about what I could not understand from the data sheet. It is not helpful when you simply copy-paste from it, like you did with questions 7 and 8. Perhaps you just don't know the answer? Or you could ask a clarifiying question if I you don't understannd, what I am asking about.

7. So how do I calculate offset (register) from offset voltage and gain from the gain coefficient?

I would like clear separate formulas Offset=? and Gain=?

8.I need more information about system calibration. Do the voltages have to be applied to both pins? Do they need to be physically applied or the inputs could be simplöy switch to ground for offset calibration and to reference voltage for gain calibration? 

10. I see I used "effective" somewhat misleadingly. What I really asked about is the unipolar mode mentioned on page 24. It says the format is straight binary, but I suspect that it is achieved by making it 2's complement and ignoring the - the negative range and thus the MSB, thus reducing the real resolution by 1 bit. Am I correct?

Thank you for your help