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Any changes in AD7367 dual power supply?

Hi, table 7 at page 16 of datasheet has changed from rev. B to rev. D. Is the new one wrong?

In my design (made on rev. B) I use +-5V analog input range and AD7367 is powered with +-5V on Vdd/Vss, I assembled 150 boards and they all work fine, except that ADC saturation is at +-2.5V instead of +-5V.

Since I'm going to produce another batch, I'm worried that something has changed on latest produced 7367s.

Could anyone from ADI clarify this or redirect me to an errata sheet?

Thanks

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  • Hi Jonathan, you have pvt about timings.

    In my application, I interface AD7367-5 to a MCU with logic at +3.3V, so Vdrive is +3.3V.

    DVcc (Digital Supply Voltage) is tied to AVcc (as suggested at page 9, table 6 of AD7367-5 rev. B datasheet) so it is 5V.

    Now I'm having a doubt: in tab. 6, RANGE0/RANGE1/REFSEL are generically referred to "logic high" and "logic low", but does "logic high" mean Vdrive, or it means DVcc? (note that in fig. 20 at page 18, REFSEL is explicitly tied to Vdrive)

    In your test, were you in the same condition of mine: DVcc = 5V, Vdrive = RANGE0 = REFSEL = 3.3V?

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  • Hi Jonathan, you have pvt about timings.

    In my application, I interface AD7367-5 to a MCU with logic at +3.3V, so Vdrive is +3.3V.

    DVcc (Digital Supply Voltage) is tied to AVcc (as suggested at page 9, table 6 of AD7367-5 rev. B datasheet) so it is 5V.

    Now I'm having a doubt: in tab. 6, RANGE0/RANGE1/REFSEL are generically referred to "logic high" and "logic low", but does "logic high" mean Vdrive, or it means DVcc? (note that in fig. 20 at page 18, REFSEL is explicitly tied to Vdrive)

    In your test, were you in the same condition of mine: DVcc = 5V, Vdrive = RANGE0 = REFSEL = 3.3V?

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