AD9681 PN9 and PN23

Question

Dear Sir/Madam, 
 Does anyone have PN9 or PN23 tables that they could share. 
 I am trying to validate hardware and the first few words of either would be of great value. 
 It is not clear if the PN9 sequence is a 14 bit register with the least significant two bits set to 0. 
 I am seeing the least significant two bits with data which could be wrong. 
 Regards Grant

grantd · Accepted Answer

Dear Sir/Madam, 
 For those who are interested i have included the AD9681 PN-9 parallel equations and PN-9 sequence. 
 signal pn9_cs : std_logic_vector(13 downto 0) := "11" & X"FE0"; 
 signal pn9_ns : std_logic_vector(13 downto 0); 
 signal pn9_twos_complement : std_logic_vector(13 downto 0); 
 .. 
 .. 
 process (Clk) 
 begin 
 if rising_edge(Clk) then 
 if Rst = '1' then 
 pn9_cs <= "11" & X"FE0"; 
 else 
 pn9_cs <= pn9_ns; 
 end if; 
 end if; 
 end process; 
 -- Next state equations 
 pn9_ns(0) <= pn9_cs(1) xor pn9_cs(4) xor pn9_cs(5); 
 pn9_ns(1) <= pn9_cs(2) xor pn9_cs(5) xor pn9_cs(6); 
 pn9_ns(2) <= pn9_cs(3) xor pn9_cs(6) xor pn9_cs(7); 
 pn9_ns(3) <= pn9_cs(4) xor pn9_cs(7) xor pn9_cs(8); 
 pn9_ns(4) <= pn9_cs(0) xor pn9_cs(8); 
 pn9_ns(5) <= pn9_cs(0) xor pn9_cs(1) xor pn9_cs(5); 
 pn9_ns(6) <= pn9_cs(1) xor pn9_cs(2) xor pn9_cs(6); 
 pn9_ns(7) <= pn9_cs(2) xor pn9_cs(3) xor pn9_cs(7); 
 pn9_ns(8) <= pn9_cs(3) xor pn9_cs(4) xor pn9_cs(8); 
 pn9_ns(9) <= pn9_cs(0) xor pn9_cs(4); 
 pn9_ns(10) <= pn9_cs(1) xor pn9_cs(5); 
 pn9_ns(11) <= pn9_cs(2) xor pn9_cs(6); 
 pn9_ns(12) <= pn9_cs(3) xor pn9_cs(7); 
 pn9_ns(13) <= pn9_cs(4) xor pn9_cs(8); 
 
 -- Offset binary to two complement 
 pn9_twos_complement <= not pn9_cs(13) & pn9_cs(12 downto 0); 
 pn9_parallel <= pn9_twos_complement & "00"; 
 7F80 
 77C4 
 F320 
 A538 
 51E4 
 7360 
 291C 
 9B54 
 44C4 
 9008 
 9184 
 B954 
 06F4 
 B720 
 2158 
 1FB0 
 12DC 
 64D4 
 B300 
 E328 
 B4BC 
 68B0 
 F594 
 1E3C 
 3A0C 
 DB74 
 02D4 
 7550 
 8A54 
 65DC 
 839C 
 C9E8 
 6A24 
 8CE0 
 DED8 
 E874 
 61FC 
 41EC 
 62E4 
 1048 
 1DA0 
 73E4 
 3150 
 0E34 
 2B88 
 E220 
 8420 
 4270 
 2B0C 
 FA6C 
 1140 
 2D3C 
 5924 
 EFC8 
 EA64 
 00C4 
 1468 
 DFD0 
 D8E8 
 4B3C 
 9F74 
 86B4 
 3B04 
 EBE8 
 2814 
 ABC8 
 6E04 
 4E90 
 75D4 
 9218 
 F0BC 
 ECD0 
 BBC0 
 Regards Grant

EZAdministrator · Answer

This question has been closed by the EZ team and is assumed answered.