I am reading the Datasheet of AD9629 Rev.0.
There is one point that is not fully clear to me:
why in the single ended configuration there is a 1Vpp signal instead of a 2Vpp (Fig.39 pag. 18) ?
Does it mean that, in case of a DC value of Avdd/2 (around 1V) on both input, positive and negative,
I can only have a swing from 1.5V to 500mV on the positive input?
Thanks for your help.