开关电容ADC 谐振匹配的问题

阅读AN-742内容,里面讲了一些串联谐振匹配的方法

Add all of the components together to find the resulting impedance seen at the secondary of the transformer. Remember, the L is added in, canceling out the capacitive term and making the input appear real.

(29.5 – j213.33) + (66 + j213.33) = 95.5 Ω

The transformer has a 1:1 impedance ratio. Therefore, 95 Ω is the impedance seen at the primary of the transformer in parallel with the 105 Ω resistor. These two resistors in parallel further yield the 50 Ω termination, 95 || 105 = 50 Ω.

问题1:变压器输入端(初级)阻抗为95Ω与105欧姆并联,得到阻抗为50Ω,那么次级阻抗应该是多少?如何计算?(以图11为例)

问题2:上图的匹配和AN-935图2的匹配有什么区别?

问题3:如果要加入抗混叠滤波器,是在谐振匹配的前一级添加吗?