Your question appears in Chinese in my browser so, I used Google to translate your question to English as:
"Is the VDD pin and ground resistance 2 ohms normal for the chip?"
Here is my answer in English:
Because this is a depletion mode device, if the gate is left open then the channel will conduct and thus the path from drain-to-ground will look like a low resistance. If Vgg were to be biased to an adequately negative voltage then the path from drain-to-ground will look like a high resistance.
Using Google to translate my answer to Chinese (Traditional), I get:
I hope that helps.