# CN0349 power consumption

Hi, I understood that CN0349 is running on 3.3v. Anyone knows the current needed?

Thank you

• The CN0349 hardware is no longer available for purchase.

However, the power dissipation can be calculated by adding up the contributions of the various components as taken from their respective data sheets:

AD5934 @ 3.3V: 15mA

AD8606 @ 3.3V: 2.8mA

ADG715 @ 3.3V: 20uA

FXO-HC536R-1 crystal oscillator @ 3.3V: 32mA

ADuM1250 @3.3V: 3mA/side, total = 6mA

Total not including ADuM5000:  55.82mA

ADuM5000 with 55.82mA load:

Efficiency of ADuM5000 supply is 28% and it must supply 55.82mA to the load.

Therefore you must supply 55.82/0.28 = 200mA to the ADuM5000 to get 55.82mA out.

The total power dissipation of the circuit is therefore approximately 200mA.

Best Regards,

Walt

• Hi Walt,

thank you for your reply. My current circuit can only power 80mA to ADum5000, does this slow the startup time for it?

Thank you

Regards

Bryan

• Hi Bryan,

If you can't supply at least 200mA to the ADuM5000, it won't regulate, the voltage output will be low, and the circuit simply won't work.

Since you only have 80mA for the circuit, I would eliminate the ADuM5000 and the ADuM1250 isolator. Maybe you don't really need the isolation?

Best Regards,

Walt

• Hi Walt,

Hi Walt,

I have would need an isolator. I have built my board and tried it out. ADum5000 is regulating at 3.3v.
My circuit looks like this
Batt(3.6) -------> 3.3v charged pump (LTC1754-3.3v) ----------> ADum5000 and ADum1250
I am also puzzled, where LTC1754-3.3v can only output maximum of 40mA, but ADum5000 and ADum1250 voltage output is at 3.3v.
Am i missing out anything? What do you think Walt?
THank you
Regards
• Hi Bryan,

Something strange is going on, because the LTC charge pump will not provide more than 40mA without the voltage dropping.

Are you sure that you don't have the AD5934 in the power-down mode? Is the entire circuit connected--including the oscillator?

Put a 1 ohm resistor in series with the output of the LTC charge pump. Measure the voltage across the resistor and you can calculate the current drawn by the ADuM5000. This will be the total circuit current including the ADuM5000.

Then the resistor in series with the output of the ADuM5000 and measure the current drawn by the actual circuit load. You should be able to track down your problem.

Something in the circuit is not drawing current.

Best Regards,

Walt