I have read that the CN 0288 evaluation board based on the AD598 LVDT signal conditioner integrated circuit offers a signal level of +/- 2.5 Vdc at the output. I need 0 to 10 Vdc. What should I do to get the signal level that I want.
Thanks for having interest of using CN0288 as your chosen reference design for your application.
For you to get a 0 to 10V voltage output, change the value of resistor R4 found from CN0288 eval board to 37.5K ohm from its 18.7Kohm defauly value .
The resistor value was derived from equation 1 and 2 under DESIGN PROCEDURE DUAL SUPPLY OPERATION section on page 6 to 7 of AD598 datasheet.
erbeThank you !