The smallest sensor output can be determined when the largest excitation voltage setting of 4.5V (VDD = 5V) and the largest PGA gain (234x) are applied. The applying equation is:
Sensor Output (mV/V) = Span (V) / [VBDR (V) x PGA-Gain (V/V)] x 1000
The smallest possible sensor output is 4mV/V.