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OP177: Improved Howland Current Source - How to Increase current output.

Thread Summary

The user is designing a high current source/sink using the OP177 op-amp and a Howland Current Pump topology. The current drops when the load impedance increases due to R5, which is unnecessary and limits the current. The final solution involves removing R5 and using a higher supply voltage to achieve the desired current output, ensuring the op-amp can operate at the higher voltage. The example provided uses a ratiometric gain of 11/10 A/V and a 500 mA R2R CMOS op-amp for improved performance.
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Category: Datasheet/Specs
Product Number: OP177

Hi forum. First of all, thank you for your global active support.

I really need your help.

In the attempt to design a very accurate, high current source/sink for an automatic test system, I came across the application notes of the AD’s OP177 op-amp discussing an Howland Current Pump (HCP) with very high current output feature up to 100mA (figure 30 of page 10 of the OP177 | Data Sheet - Rev.H). Following the indication of the note describing a “Bilateral Current Source” basically a Howland Current Pump and adding 2 power transistor, with a load resistor of about 100 ohms you actually can get a current of -100mA / +100mA. (Source/Sink).

But as the Load Impedance increases to 200mA it drops to 60mA and so on.

I attach the LTSpice Simulation  4555.Figure 30. Bilateral Current Source - 100mA CURRENT SOURCE.asc

Now I need a stable current source/sink with very large load impedance interval (from 200 to 1.2k).

That’s why I have chosen the Howland Current Pump topology since one of its feature is to provide the same current with load change.

How is it possible to increase the current without driving the OpAmp into saturation?

Best regards and thanks.

Houseman

Edit Notes

moved & updated form
[edited by: lallison at 4:39 PM (GMT -4) on 6 Jun 2022]