Please refer to below circuit. If 3.32V of IN- and 3.27V of IN+, output of LT6000 is 0V. If 3.21V of IN- and 3.27V of IN+, output of LT6000 is 3.3V. The results looks normal.
But for below red circle. If 0V of IN- and 3.27V of IN+, why is output of LT6000 0V ? Is it correct? Thank you.
If I understand it correctly, you have used the LT6000 as comparator with IN+ as your reference pin.Your reference voltage is fixed at 3.27V coming from the Voltage Divider Network.
When your IN- voltage…
When your IN- voltage is higher than IN+(3.32 in your 1st case), the Vout is 0V.When your IN- voltage is lower than IN+ (3.21 in your 2nd case), the Vout is 3.3V.This results are normal and expected.
For your 3rd case, you have 0V at your IN- pin and that is lower than your IN+ pin, the output should be 3.3V.I would like to know how did you implemented 0V in your IN- pin here?
Thanks and regards.
Customer directly short to GND on IN- pin. Thank you.