I am using a 6-axis load cell which has a built in amplifier. However, the output signal is differential and the analogue inputs on the control unit are single ended (0V to 5V).
Therefore I need to convert the load cell differential signal to single ended (0V to 5V).
I was wondering if I could use an AD8426 instrumentation amplifier to convert the differential signal to single ended and if so how ?
Details about the load cell are below (M3815C) :
- https://www.srisensor.com/m38xx-series-6-axis-ft-sensor-for-low-capacity-high-product/
- https://www.srisensor.com/uploads//M3815C.pdf
The full scale for each channel is 5V...
I have assumed that:
- +SIG can swing from -2.5V to +2.5V (with respect to ground)
- -SIG can swing from -2.5V to +2.5V (with respect to ground)
My understanding is that +SIG and -SIG are always the same magnitude, just opposite polarities. In which case the behavior is shown in the animation below...
I used the online tool to simulate the circuit. Are the following parameters correct ?
- Vs = +/-12V
- Gain = 1
- Vref = 5V
- Vcm = 0V
As the output is 10V I was thinking of using a potential divider to scale it down to 5V (the simulation does not allow a gain of less than 1).
Edit Notes
Revised understanding of differential signals (+SIG and -SIG are always the same magnitude, just opposite polarities) and added GIF[edited by: skyrat at 3:49 PM (GMT -5) on 27 Nov 2024]
