We will drive AD8557 by Vdd=3.3V single power supply.
1)
So what is the Input Voltage Range at this time Vdd=3.3V?
3.3V-1.2V=2.1V
I think that the Input Voltage Range is 2.1V.correct?
2)
If I did the good catch, Why 1.2V?
Does it come from 2 diodes Vref internal?
Just now when Vdd=5V, Input Voltage Range is 0.6V to 3.8V we can confirm.
5V-1.2V=3.8V
And when Vdd=2.7V, Input Voltage Range is 0.6V to 1.5V also we can confirm.
2.7V-1.2V=1.5V
I think my catch from above.......
Thanks, Kaos
