Hi,
I'm using the difference amplifier AD628 (exact model AD628ARMZ) in our circuits and we are having issues which seem to be caused by the offset voltage. To identify if the parts used here are within their spec, I would like to calculate the offset voltage based on the information given in the datasheet.
Now it is not fully clear to me, how to calculate the offset voltage given by the datasheet correctly. The datasheet gives values for the output amplifier only, for the difference amplifier only and for the combination of both.
I want to calculate the offset voltage for an operating voltage of +-15V and a common mode voltage of 43V. Furthermore, the external resistors for setting the gain of the output amplifier are chosen with 2kR and 118kR which results in a maximum gain of 60.2 (resistor tolerances are taken into account here!).
According to the formula mentioned in note 2 on page 4 of the datasheet, I should have a total output offset voltage of
V_offset = (0.1 * 43V) / (10^3.75) * 60.2 = 46.03mV
Of course, temperature has also an impact, but this is neglected for the moment.
Now my question: Is the calculation above correct for the complete amplifier (i.e. the combination of the difference amplifier and the output amplifier)? Does the formula mentioned in note 2 refer to the combination of both amplifiers?
Or, is the calculation above wrong and the 46.03mV caused by the increased common mode voltage and calculated above add up to the already existing offset voltage at V_CM = 0V (in my case would that be +-1.5mV * 60.2 = 90.3mV offset at a common mode voltage of 0V)?