Bandwidth of AD8000 in non-inverting configuration

I have a AD8000 SOIC package in noninverting configuration (Fig. 50 datasheet). Rf=439 ohms, Rs=0ohms, RL is open circuit, Rg = open circuit, 0.1 uF decoupling caps at supply pins. I am using +/-5V supply. I am interested in the performance at 1.25 GHz. I use -20 dBm input and get -26 dBm output at 1.25 GHz. I don't think this matches the performance shown in Fig.5 of datasheet. Can you suggest what I could change to make it work as expected?

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  • Hi Jino,

    Thanks for your response.

    The figure 5 of the datasheet does not match Table 5 (Gain = 1 for SOIC). Why is that?

    Could you elaborate on the parasitic capacitance you refer to. I have made sure there is no ground plane underneath the high speed signal traces. I do have a ground plane underneath the chip as in the datasheet (smaller than the datasheet with fewer vias). Let me know if you have layout recommendations. I have tried to follow those in your datasheet.

    Also, if would be great if you have a sample gerber for this AD8000 SOIC chip, noninverting circuit. (Figure 50)

    Thanks and look forward to your response.

    Best regards,

    Atul

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  • Hi Jino,

    Thanks for your response.

    The figure 5 of the datasheet does not match Table 5 (Gain = 1 for SOIC). Why is that?

    Could you elaborate on the parasitic capacitance you refer to. I have made sure there is no ground plane underneath the high speed signal traces. I do have a ground plane underneath the chip as in the datasheet (smaller than the datasheet with fewer vias). Let me know if you have layout recommendations. I have tried to follow those in your datasheet.

    Also, if would be great if you have a sample gerber for this AD8000 SOIC chip, noninverting circuit. (Figure 50)

    Thanks and look forward to your response.

    Best regards,

    Atul

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