Regarding quiescent current of AD8130 Differential receiver.

Hello DeepakD ,

13.9 mA is the max current that will be drawn individually from both +12V and -12V supplies.

Best regards,
Paul

Hi Paul,

Does it mean, 13.9mA is drawn from +12V and 13.9mA is drawn from -12V.?
Does it means the total Current drawn from this IC would be two times of 13.9mA i.e 28mA??

Hello DeepakD,

Apologies for the confusion.13.9 mA is the max current that can be drawn from the positive supply (+12V) and the max current that can sink on the negative supply (-12V). To sum it up, the total current (max) is still equal to 13.9 mA. To understand it better, here is an LTSpice simulation using AD8130:



As can be seen on the simulation above, the part draws a current of 10.409 mA from the +12V supply and sinks a current of -10.409 mA to the -12V supply. The current flows from the positive supply pin to the negative supply pin of the op amp.

I hope this helps.

Best regards,
Paul

Hello DeepakD,

Apologies for the confusion.13.9 mA is the max current that can be drawn from the positive supply (+12V) and the max current that can sink on the negative supply (-12V). To sum it up, the total current (max) is still equal to 13.9 mA. To understand it better, here is an LTSpice simulation using AD8130:



As can be seen on the simulation above, the part draws a current of 10.409 mA from the +12V supply and sinks a current of -10.409 mA to the -12V supply. The current flows from the positive supply pin to the negative supply pin of the op amp.

I hope this helps.

Best regards,
Paul