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Trying to understand AD8138 circuit from legacy design

Category: Hardware
Product Number: AD8138

I am working with a legacy design using an AD8138 to drive an ADS5281. I'm trying to understand the following circuit:

The feedback resistors are symmetric at 1k2, but why are R65 and R63 split as they are, and what is the purpose of the R74/R68/R66 network? Why are the input resistors not simply symmetric?

C1ROH is an analog input from a back-plane connector. The input range is supposedly +/- 3V. The ADS5281 has 2 Vpp input range.

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  • Hi  ,

    Good day. To further help you with your inquiry, I would like to clarify some details of the question. May we clarify where did you get the circuit presented above? Also, is the input range +/- 3V is equivalent to C1R0H? Lastly, what was your intended output level?

    Regards,
    Gilbeys

  • Hi Gilbeys,

    thank you for your reply. The circuit is from a legacy design we're working on, where the original designer is not available anymore. I'd like to understand the implications of the resistor circuits for a possible redesign.

    The The C1ROH input range is supposedly +/- 3V. The output should match the ADC's range, which is Vcm (1.5 V) +/- 0.5 V for each input, or 2 Vpp differential swing.

    Thanks,

    Thomas

Reply
  • Hi Gilbeys,

    thank you for your reply. The circuit is from a legacy design we're working on, where the original designer is not available anymore. I'd like to understand the implications of the resistor circuits for a possible redesign.

    The The C1ROH input range is supposedly +/- 3V. The output should match the ADC's range, which is Vcm (1.5 V) +/- 0.5 V for each input, or 2 Vpp differential swing.

    Thanks,

    Thomas

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