Hi,
I designed system thats monitoring batteries discharging.
There are a lot of batteries sampled by AMP03 (Unity gain, diff. amp) then transfered via 2 analog 32-1 MUX (ADG732) and analog MUX 2-1 (ADG1219) and finally driven through the another unity gain amp to NI A/D in the PC.
After some months of working the battery sample amps started to burn up at random order.
May I miss anything in the design, espessialy in AMP-MUX interface?
Thanks
Harry,
Thank you for your response.
The AMP03 is not Instrumental Amp, but precision unity gain diff amp.
you can see the whole datasheet here http://www.analog.com/en/products/amplifiers/specialty-amplifiers/current-sense-amplifiers/amp03.html
There are internal resistors inside the component. I connected the AMP like described in application circuits:
What happens sometimes is that the mux input (connected to AMP03 output) is stuck in -0.5V, I suppose that's clamped by internal diode.
I tried to add a series resistor between Amp and MUX (100R, 1K, 10K)
I tried to connect Amp like a summing Amp (E1=E2=Battery => gain = 2) and on output I put voltage divider (two 10K resistors)
So that's working, but when I connected it to MUX I get -0.5V in the MUX input, WHY?
Thanks again,
Alex
Harry,
Thank you for your response.
The AMP03 is not Instrumental Amp, but precision unity gain diff amp.
you can see the whole datasheet here http://www.analog.com/en/products/amplifiers/specialty-amplifiers/current-sense-amplifiers/amp03.html
There are internal resistors inside the component. I connected the AMP like described in application circuits:
What happens sometimes is that the mux input (connected to AMP03 output) is stuck in -0.5V, I suppose that's clamped by internal diode.
I tried to add a series resistor between Amp and MUX (100R, 1K, 10K)
I tried to connect Amp like a summing Amp (E1=E2=Battery => gain = 2) and on output I put voltage divider (two 10K resistors)
So that's working, but when I connected it to MUX I get -0.5V in the MUX input, WHY?
Thanks again,
Alex
